Homework Help

[Rain]

Despite how the title may make it sound, no I don't need any help (at least right now:p), but I figure this is a good thread to have.

If anyone needs help with school/homework or anything and even wiki can't help just post here and hopefully someone can help out

Subjects and who can Help
Maths
-Avidlinuxuser
-Avi
-Rain
-emoloz
-Grey1x

Sciences
-.nez (bio, chem)
-spacecat
-Jhaxe (enviromental)
-Avi (anotomy)
-Rain
-Grey1x

Languages
-Jhaxe (japanese)
-.nez (japanese)
-spacecat (japanese)
-Rain (spanish)
-Jaws (mandarin chinese)
-Kolbertt (spanish and French)
-Poiison (english)
-Revan1990 (english)

Psychology
-emoloz
-Malaena

Other subjects
-Unicorn (marketing, and with essays)
-emoloz (sociology, ICT, citizenship, debating, RE)
-Avi (relgion)
-Stark espada (History and Computers)
-Poiison (music)
-Revan1990 (religion)
-Malaena (Philosophy, Sociology)

If you need help with anything either post here or send a person a PM (but don't expect real quick answers that way)

[avidlinuxuser]

:p I can help people on mathematical stuffs. I can help anyone with calculus, linear algebra, multi variable calculus, finite mathematics, proofs, college algebra, trigonometry/precalculus, and geometry. I can also help with programming stuff. :yay

[Jhaxe]

@avidlinuxuser- I may need your help at some point in time.

Good idea, Rain ^^

I suppose I can offer my services too, if there's anyone in Japanese 1, Environmental Science, or English, my fortes.

Also, if there's anyone in Japanese 2, Chinese 1, Biology, or Algebra, and wants a study partner, I can do that too =3

[Flying Banana]

o.o! yayy! a helping thread xD i seriously need this xP me and my friend were gonna make one in BF but we didn't know if it was okay :p
but thanks for making it Rain =DD

[Rain]

Flying Banana- I never know if its ok to make a thread, I just do it and let the mods decide:lmao

After a while I'm going to post a list of people who can help in a specific subject (like how avidlinuxuser just said he'll help with math). I figure if I do that people can also PM people it might be easier:p

Subjects I can help with:
Spanish (at least the earlier levels)
Math
Sciences
and probably some more

[spacecat]

Well if it's school work I graduated already and did really well in most things so if you need any help I am available. Probably best to ask about English, Science subjects, Japanese etc.

[negativzero]

English
Japanese
Biology
Chemistry

I could help anyone in those ^__^

[Unicorn]

I can help (try my best to, anyway) with english, editing essays, or marketing subjects...

[Avi]

I can help with the same as Uni, and adding World Religion, Human Body, Applied Calculus(Which I missed a few classes and I'm going to learn it now >_< ), and all the lower maths as well.

[aznxenocide]

Alright guys, first question.

I'm having trouble with series and determining whether or not they converge or diverge. I know I can integral test or ratio test, but there SHOULD be an easier way of determining convergences...any help?

[Rain]

aznxenocide- what subject is this, just math?

All i can think of right now is just look at their rates of change (slopes may be the better term), and that'll tell you if they converge, but you'll have to work it out to figure out when

[aznxenocide]

For series? o.O

No, that's definitely not true....XD Yeah, it's math.

[Rain]

I'm not familiar with "series", what is it (what type of math or what application or something).

I guess that since I have no clue what you're talking about, I probably can't help you:( but I'll keep trying:D

[Jaws]

Sorry Xeno ... can't help with anything related to math ( I flung it ) ^^;

If anyone needs help with Mandarin Chinese, I'll take the job ^^

[aznxenocide]

I'm not familiar with "series", what is it (what type of math or what application or something).

I guess that since I have no clue what you're talking about, I probably can't help you:( but I'll keep trying:D

lol don't worry about it. It's calculus. ^.^

There HAS to be someone here who can though...XD

[Rain]

I was planning on taking calc next semester:D so I can help you in about 6 months:lmao

I'm sure that someone here can help, eventually.

Damn, so far this thread is 0 for 1:(:cry

[Sora Chan]

Is that BC calc because I don't remember anything in AB with series.

[aznxenocide]

Er yeah...we learned about hardcore series in the class after Calculus BC...although series show up do show up on the BC test. It's just been so long since I've done any calculus...XD

[Avi]

Alright guys, first question.

I'm having trouble with series and determining whether or not they converge or diverge. I know I can integral test or ratio test, but there SHOULD be an easier way of determining convergences...any help?


No idea but Wikipedia could help, it's so great. I love college professors who contribute to Wiki :D:
http://en.wikipedia.org/wiki/Convergence
http://en.wikipedia.org/wiki/Integral_test_for_convergence#Borderline_between_d ivergence_and_convergence

[aznxenocide]

lol yeah, I tried that. Wiki's not known for being very helpful when explaining discrete stuff like that. Especially with all the proofs...XD Thanks though. :p

[emoloz]

I can kinda help with a range of stuff more so ICT, Math (not like crazy math but easy Math), English, Sociology, Psychology (college level) , RE, Citizenship and debate topics.

Well i could do with gaming help if any of you geeking gaming nerds could give us a hand. Well I have this ICT artwork assignment to complete and design a game. I have chosen Bomberman as the game to draw (because of my poor drawing skills). The thing is we have to change this Video game into a board game, and i have not a lot of ideas on how i could do this. Any ideas?

The only thing i could think of is that you kinda role a dice on a board and you have to move around it. The stop movement there will be places with bombs which make you move back on the board. Also like monopoly where you get community chest and stuff and that either give you places to move or play tricks on other players. Though I don't know how to make to make the player win though if i do this xD

[Rain]

Hmmm, I don't know much about bomberman, but I do know about board-games:D

Make it like a dice-rolling game, where you could still get the "community chest" type cards. Have those bombs simply "hurt" the player instead of moving him back and the last player left alive wins:cool:.

[emoloz]

The thing is how would i work out the hurt bit and stuff. Like have like 10 lives and like if you get a special card it adds lives to the player? Sounds a bit confusing XD.

[So-Dee-Lish-Us]

Guitar question here.. D:
What's the finger placements, for the chord: Cadd9?
I'm trying to learn how to play this song. :3
This isn't part of my homework..but I have a guitar class as an elective. XD

[Flying Banana]

yeah...but you already know how to do the homework for the class >__> so you dont get the extra credit :P i'm barely learning the thing now xD

[So-Dee-Lish-Us]

=o
Weellll....If I could play the song I'm trying to play, I could play it in the up-coming winter concert. =P
And that's part of our grade..I think. xD

[aznxenocide]

http://www.all-guitar-chords.com/index.php?ch=C&mm=add9&get=Get

[emoloz]

Anyone know an good colouring tutorials for Photoshop need it to colour my bomberman in that i have drawn xD.

[negativzero]

what kind of colouring are you looking for? cus i can teach a thing or two about colouring.

[Rain]

I don't use photoshop that much, so I have no clue

*feels useless in this thread*

when i do use photoshop i just mess around until something works, maybe you could try that:rotflmao

[emoloz]

what kind of colouring are you looking for? cus i can teach a thing or two about colouring.

Just so i can colour bomberman the characther XD. I don't need anything too bing bang bosh. As long as it looks good. I also need a line tutorial like how you draw around your image without going of the lines.

@Rain: I have messed around before i was just wondering if anyone knew anything specifically good thats all.

[negativzero]

ok then, for colouring bomberman, all you need are the default brushes, the blur tool, smudge tool and the opacity tool, and a lot of layers. it does take a while tho, cus u need to be a little delicate with the brushing, cus shadowing is a little difficult if you apply too much pressure on it. also learn to delicately use the gradient tool, as it can cut a few steps here and there xD

how to trace an image? use the pen tool, u need to master it cus its important to photoshop really, so go look up some pen tool tutorials.
this tutorial should suffice for now
http://www.melissaclifton.com/tutorial-pentool.html
for more advanced pen tool stuff, i suggest you pick up illustrator.

[emoloz]

Ah yes the pen tool. I was thinking of using that crafty thing XD.

The rest to me sounds like i want to scream real loud and give up but thats just pointless. You like have to colour each section and build it up yeah? Sounds like this shall be ultra fun xD. Well i am always up for a Photoshop Challenge. They don't call me Emoloz for nothing XD.

[aznxenocide]

You've never played with the pen tool before? It's like, one of the most versatile things in Photoshop, EVER. And duudde. Deviantart is such an awesome resource for coloring...everyone good posts tutorials on their technique, so you can learn from them too.

[emoloz]

Yeah i have used it before, duh who hasn't come on XD. I just wondered what ideas people on here have thats all since some colour more oftern than not on their art. Better asking the experts before jumping in head first no? Yeah gotta love DA for its tutorials XD

[aznxenocide]

Are you trying to do cel shading? Or like...badass gradient shading stuff?

[emoloz]

Meh i just found out i don't actually have to colour this artwork in for my assignment. Good job i aint started xD.

AZN: I was just going to colour it in nothing fancy really XD. Just solid colours like bomberman is.

[aznxenocide]

oohhh. haha yeah Bomberman.

But you should TOTALLY play with the pen tool. Just for future reference, so you know how to use it. ^.^

[emoloz]

Yeah i think i have to colour him later am going to ask because this assignment is all crazily explained. Yeah i will do because i still need to get the hang of it. Tis a bit crazy. Though saying that trying to draw with a laptop mouse using the pen tool isn't the most easiest of tasks. Shall have to get myself a mouse.

[Jhaxe]

Jhaxe needs HW help today. I was sick and didn't go to school today, but I have an Algebra quiz tomorrow. I have the HW but I don't understand the second part, it's something I didn't learn in Algebra 1. It's 'Compound Inequalities.'

I don't get the concept without the lesson. What does the 'and' and 'or' between the two inequalities mean? And when adding the inequalities do you just add the same sides?

[Rain]

Inequalities, huh I hope I can help explain this:headscratch

Hmm, it may be easier if i saw a few of your problems but,

when adding the inequalities, you can add them just as you would for normal equations, but keep the signs you have

when you have the and/or you can just combine them

x>3 and x< 10 becomes 3<x<10

if it helps google ask doctor math, they can really help :)

[Jhaxe]

yeah, I see how you do that. These are a bit more complicated...let's see...
(<_ means less than or equal to, best I can do with the keyboard) What about the 'or'?

9x < 54 and -4x < 12 (Do I solve each inequality and then put them together like you showed?) Would that be...

x < 6 and x > -3

to

6 > x > -3

Is that right?

Now about the 'or'? like this...

6(x + 2) _> 24 or 5x + 10 <_ 15

6x + 12 _> 24 or 5x <_ 5

6x _> 12 or x <_ 1

x _> 2 or x <_ 1

What do I do with the 'or'?

[Rain]

When you have the one inequality, you do simplify each then combine (your example was right)

From what i can remember you do nothing with the "or". You just leave it as x> a number or x< a number

you should ask your teacher for the lesson so you can get the correct lecture:D

[Jhaxe]

Thank you =3 I didn't have my textbook, so I was kind of at a loss >< I'll ask her tomorrow if there's any else I missed.

[Dice]

I need help with a question for a friend:

120 people go to the circus and pay a total of $120 dollars. Men cost 5, women 2, and children 10 cents. How many of each go.

How do I figure this out? What's the thought process :love

[Slev]

I hope I did this right. Looking at this question without weird modulus things that are clinging to the edge of my memory:

x:men, y:women, z:children

120 = x + y + z

y=120-x-z

120 = 5x + 2y + z/10
120 = 5x + 2(120-x-z) + z/10
120 = 3x + 240 - 2z + z/10
19z/10 - 120 = 3x
x = 19z/30 - 40

Obviously the number of children has to be a multiple of 10, otherwise there would be no way for the total money to be a whole dollar.

And since x > 0, 19z/30 - 40 > 0.
19z/30 > 40
19z > 1200
z > ~63

So z can only be a multiple of 10 greater than 63, which limits our choices to 70, 80, 90, 100, and 110.

x = 19z/30 - 40

Since z is being divided by 30, it has to be a multiple of 30 to make x a whole number. Thus, the only possible value of z is 90.

x=17, y=13, z=90.

[Dice]

Wow - thank you so much casanova :inlove :inlove

[avidlinuxuser]

Just to throw a hard problem out there. Let's say you are given set of radii, x-coordinates, and y-coordinates. Your task is to how the points by angle and radii. You can't use trig functions or division. I'll post the solution up if no one figures it out. General descriptions will suffice.

[aznxenocide]

Polar coordinates, homie.

[avidlinuxuser]

You can only use addition, multiplication, and subtraction since you can multiply by -1. Therefore, it's impossible to convert to polar coordinates. It doesn't seem likely that anyone will get it so.... Here's the answer. You partition the triples into four segments by what quadrant they are in. Looking only at the first quadrant, given P1(x1,y1,r1) and P2(x2,y2,r2) Angle(P1) > Angle(P2) if x2*y1 < y2*x1. If x2*y1=y2*x1, angle(P1)=angle(P2). In this case, you sort by radius which is trivial since you are given the radius in the triple. You use the symmetrical nature of the circle to sort the other three segments. Finally, you merge the four segmented sets together with the sorted set of triples in quadrant I coming before the sorted sets of triples in quadrant II which come before the sorted set of triples from quadrant III which come before the sorted set of triples in Quadrant IV.

The key to the solution was to realize that it's trivial to test points that lie on the x and y axes. The only thing you need to now is that the invTan(very large number) is approximately 90 degrees. Therefore, y/x is tending towards to infinity as the angle gets closer to 90. Therefore y/x is getting larger. If y1/x1 > y2/x2, the angle for (x1,y1) > the angle for (x2,y2). Now, division is not allowed but multiplication is. Therefore, you cross multiply. x1*y2 > x2*y1 which is the desired answer.

[Rain]

You posted here just to give us a hard problem:mad: just kidding you:hug

thanks for giving us that answer, someone may need it in the future

[avidlinuxuser]

One, the definition of the problem says no trig operations or divisions. So, that's eliminated to start with. As far as the practicality of the problem. Trig operations are among the most expensive functions on a computer since it is the result of a large number of additions, multiplications, and subtractions. I am sure you are familiar with the taylor series for the trig functions. Moreover, if you wanted to sort points as quickly as possible, it's much more efficient and less taxing on a system to use the relation that I described in my solution.

[FireCandy]

I've got some problems with Mixed Conditionals (you can start laught now).

The main problem is that I've got one day to found out what is that and translate 50 sentences :cry

I don't have enough time to search all those sites (I'll be home at 9 p.m.)n - I just need someone who will say 'You use it when... and write it like ....'

Help anyone?

[Rain]

FireCandy- :headscratch what subject is this math, logic, something complately different

[FireCandy]

It's English xD

[Rain]

Oh so its conditional sentences in english, I still don't understand:o

This may be wrong (for what you're looking for), but the conditional tense is a form of a future tense. you use it to say something you would do but the action won't happen
Example
Person 1- "If I give you money, will you go the store for me"
Person 2- "I would go, but I don't want too"

this isn't a great example, but I think it works

[imamess]

It's an English thing. If I (blank) then I (blank) is a normal conditional statement like in math (and programming), but a mixed conditional is mixing two different tenses like describing if something happened in the past, then something else would happen in the future and vice versa. this site explains it pretty well (http://www.englishpage.com/conditional/mixedconditional.html)

This just reminds me of learning plus-que-parfait in French, and my teacher kept on insisting that plus-que-parfait is plus-que-fun! It made me want to hurt her, and not because it was hard. It was just really annoying to hear twice daily in an hour class.

[FireCandy]

I know about 'normal' conditionals. I didn't know what was that 'mixed' thing. Thank you imamess :hug

Now just to print that and I can do my homework xD

[ShadarHaran]

Dose any one know any good books or websites on learning Japanese, and reading and writing it?

[aznxenocide]

Rosetta Stone

Does anyone know anything about partial orderings?

[avidlinuxuser]

partial orderings as in partially ordered sets(posets)?

[aznxenocide]

omfgyes

What about least upper bounds/greatest least bounds?

Actually...

If we assume that the relation < is a partial ordering on C, would the theorem that, for every point p on C, there exists a region containing p, still hold?

C is the continuum, which has at least one point and has no first point and last point.

A region is defined as:

Let a,b be points in C such that a<b. The set of all points that lie between a and b is called the region (a;b).

My intuition tells me that it shouldn't be possible...since you can't define a region in terms of only one point, so if < were a partial ordering, there may be a couple points that may not belong to any region. But how would I prove that?

[aezirka]

Friggin... I should have posted my Macro homework here -__-

Pebbles: Figured it out. Well, not exactly me because I had to look at a previous student's work. But apparently I was doing it right >.>

[aznxenocide]

I'm SOOORRRRYYYYYYY

T.T

[avidlinuxuser]

I'm familiar with a least upper bound, greatest lower bound. As for the relation
a < b, it violates the statement that if S is a poset than S is refexive. a is not strictly less than itself. S is also not antisymmetric rather it is a asymmetric since if a < b, b>a and b can never be equal to a.

The region you are defining is however a valid strict weak ordering which is a subset of strict partial orderings. Generally, we use posets(partial ordering) to denote non-strict partial ordering. If every a,b elements of S can be compared, we can create a total ordering which again is just a subset of a partial ordering.

In conclusion, it's actually quite a simple. The proof is not in show that points exist outside the region but rather to show < can not be a poset since it would contradict the definition of a poset(non-strict partial ordering) since it is irreflexive.

[aznxenocide]

....wtf?

We're given that < is a partial ordering. And we have to determine whether or not there exists at least one region containing any p on the continuum.

And we have to show that points exist within the region. Reflexivity isn't a property of partial orderings to begin with.

[FireCandy]

Dose any one know any good books or websites on learning Japanese, and reading and writing it?

I need to know your native language first.

[Danna]

Well, I can help with learning Japanese cos I'm also doing it myself xD Basically, I think 'Minna no Nihongo' book set is a good start for beginners from any native languages. Then, there are 中級へ行こう and ニューアプローチ中上級日本語. I also recommend any Kanji books that you can practice writing 'cause those books are pretty the same. You probably can take JLPT 2 after finishing them all.

Though, I really need some advices for studying Chinese >< No matter how much I try, I can't differentiate the sounds between qi and xi, ca and sa. I think I can do other things very well except for writing pinin and 声調 -_____-;; (or is it just that I've been playing too much in the class?:headscratch)

[avidlinuxuser]

....wtf?

We're given that < is a partial ordering. And we have to determine whether or not there exists at least one region containing any p on the continuum.

And we have to show that points exist within the region. Reflexivity isn't a property of partial orderings to begin with.

Posets, in normal use, refers to sets that are reflexive, transitive, and antisymmetric. It's also possible to have a poset that is irreflexive, asymmetric, and transitive. In this case, you have strict weak ordering. Anyway, what items are you using in the problem. If we're talking about < on the set of numbers, there's always a region (a,b) that satisfies the condition a < p < b. Since p-1<p<p+1. Note, that every point in the region must be comparable. If there exists any points p in C that cannot be compared to any other point in C. p cannot be encapsulated in a region bounded by the region (a,b).

If you need proof of the property of a general partial ordering, here's a small set of notes from an MIT class, http://courses.csail.mit.edu/6.042/fall06/lec10.pdf
It states quite clearly that a partial ordering is reflexive, antisymmetric, and transitive.

[aznxenocide]

That's not a poset, that's a totally ordered set.

For a partial relationship, the statement that if x =/= y, then x<y is false. Which is why it's really not as simple as you think it is.

[avidlinuxuser]

That's not a poset, that's a totally ordered set.

For a partial relationship, the statement that if x =/= y, then x<y is false. Which is why it's really not as simple as you think it is.

Totally ordered sets are a subset of posets which is why i state that all points a and b have to be comparable in order for any p in C to be contained in the region (a,b). If you're talking about posets being reflexive, look at the notes I posted from an MIT course. Partial orders are reflexive, transitive, and antisymmetric. Ctrl+F to find partial orders or posets.

Edit: x=/=y, then x < y is false regardless of whether or not x and y belong to a poset if x > y. The correct statement would be to state that a point is incomparable if neither x < y or y < x which can indeed happen in a poset. The solution is to show that there exists some p in C which is not comparable. That's all you need to prove. If there does not exists a p in C which is not comparable to two other points with a < p < b, then p can be encapsulated in the region (a,b). Otherwise, p can not be encapsulated in any region. In other words, most of the proof lies in what is being compared and how < is defined.

[aezirka]

I'm SOOORRRRYYYYYYY

T.T

WTH don't be -___- You're not required to help me~

[Kolbertt]

Well, if someone needs any kind of help with spanish or french, I can surely give them a hand, just PM me-

Don't worry, my spanish is MUCH more better than my sucky english :P- French... at around the same lvl

[aznxenocide]

If there does not exists a p in C which is not comparable to two other points with a < p < b, then p can be encapsulated in the region (a,b). Otherwise, p can not be encapsulated in any region. In other words, most of the proof lies in what is being compared and how < is defined.

Exactly. So as long as p is incomparable to all the other elements, then there doesn't exist a region that includes point p. Right?

[avidlinuxuser]

Exactly. So as long as p is incomparable to all the other elements, then there doesn't exist a region that includes point p. Right?

Correct. The proof only lies in showing that at least one point is incomparable by the definition of your partial order.

[Rain]

Kolbertt- you'll help with spanish and french, cool :hug *goes to add you to list*

[So-Dee-Lish-Us]

1. -83 - (-48) - 65 =

2. 32 - (-17) - 32 =

3. Write a numerical expression for the phrase. Then simplify.

The Glasers had $317 in their checking account. They wrote checks for $74, $132, and $48. What is their checking account balance?


I'm not so good at subtracting integers. >.>
Well, at least the ones with 3 or more numbers. =o

[Jaws]

I really need some advices for studying Chinese >< No matter how much I try, I can't differentiate the sounds between qi and xi, ca and sa. I think I can do other things very well except for writing pinin and 声調 -_____-;; (or is it just that I've been playing too much in the class?:headscratch)

hmmm ... not sure if I'll be helpful or not, but try the following :

qi = chi ( as in Chip )
xi = see
ca = ch-a ( this is a difficult one to explain since there are no such sound in English. Best way to explain this will be say combining the ch ( in Chip ) and a ( in Amazon )
sa = sa in Safari

For pin-yin and sheng-diao I'm not sure what it is you need help with? So please PM me with more details and I'll try to help the best I can :)
Hopefully, my attempt at sound differentiating is helpful ^^;

[stark espada]

I can do history if you need help with it. Its my other speciallty other then computers. I am very good at it so I guess you can sighn me up for it.

[Rain]

So-Dee-Lish-Us

1. -83 - (-48) - 65 This is the same as -83 + 48 -65, just take each part at a time. -83 +48 is -35 then -65 so thats -100

2. 32 - (-17) - 32 is just like 32 +17 -32, which will just be 17.

With addition and subtraction the numbers can be combined in any order, as long as each number always keeps the sign it has

3. 317- 74- 132- 48 Just take each part and simpify from there, don't worry about doing it all at once. 317-74 is 243, subtract 132 from that and you get 111 and take another 48 away and the answer is 63


stark- thanks for being willing to help:D

[stark espada]

your welcome rain.

also i just replaced the worst mother board I had ever seen it was broke in 8 different places I did not know how he did that.

[hemagoku]

need help with this ,not the answer i just want to know how to solve it

http://i149.photobucket.com/albums/s80/hemagoku/01032008039.jpg
the one on the left

[Rain]

f and g are both linear equations, so they have the equation y= mx +b

if you figure out the equation for both f and g, then you can get the values for a and b, then just subtract them

if this isn't clear enough i can show you how to do part of it:D

[hemagoku]

f and g are both linear equations, so they have the equation y= mx +b

if you figure out the equation for both f and g, then you can get the values for a and b, then just subtract them

if this isn't clear enough i can show you how to do part of it:D
i am not good with graphs can u explain more ?

[Rain]

sure

first you need to find the equation for f

and based on the table you know 4x=5 and 12x=9

if you set those equal you can find the slope of the f

solve for x you get 4= 8x x= .5, thats the slope (m)

then you can use that to find the equation fo f, which ends up as y=.5x+3

then you can plug 8 in to find the value of a

does that help

[hemagoku]

4x=5 and 12x=9

if you set those equal you can find the slope of the f

solve for x you get 4= 8x x= .5, thats the slope (m)

then you can use that to find the equation fo f, which ends up as y=.5x+3

then you can plug 8 in to find the value of a

does that helpi don't get all that :o :(

[Rain]

sorry, im not great at explaining over the internet, ill try to make it easier this time

the goal right now is to find the equation of f

first you need the slope, slope is the change is in y divided by the change in x.

so, take (9-5)/(12-4) which is 4/8 which is .5

thats the slope of f

you know that (4,5) is on f so you can use the slope to find the overall equation

using point-slope form y-5=.5(x-4)

y-5=.5x-2
y=.5x+3 if the equation of f

sorry if this is confusing

once you have the equation of f, you do the same thing for g, then you can find a and b

[hemagoku]

ok now i got all that but still can't figure out how to get a and b after getting the equations

[Rain]

this is for a

take the equation f

y=.5x+3

and plug in the vakue of 8

y=.5(8)+3

y=4+3

y=7

7 is your a value

do the same with g to get b

[hemagoku]

this is for a

take the equation f

y=.5x+3

and plug in the vakue of 8

y=.5(8)+3

y=4+3

y=7

7 is your a value

do the same with g to get b
thanks man i got it at last

[Rain]

no problem

here are the answers if you want them

equation of g is y=.2x+3
b= 5
so the overall answer is 7-5 or 2

to any mod- could you merge this into the homework thread i made, instead of closing it:D

[hemagoku]

its 2 as i made it b4 ,i posted it here cuz the answer key said 4 and i believed it :@

[Rain]

the answer key said 4:headscratch

I have no clue how it has that, im quite sure its 2:lmao

the answer key is probably just wrong:D

[hemagoku]

i would rep u but can't :(

[Rain]

no problem, i didn't help you so I could get rep :rotflmao

if you have any more questions feel free to post them here or in the homework thread:cool:

[hemagoku]

no problem, i didn't help you so I could get rep :rotflmao

if you have any more questions feel free to post them here or in the homework thread:cool:
k thanks again .

[Skorpz]

i need help on math geometry.

i have to find the measure of D on a parallelogram. A= (8x+33) and D= (7x+27) and A and D are consecutive angles. how do you solve it

[Rain]

do you have a pic you could maybe post

i think on a parallelogram two consecutive angles have to total up to 180 degrees

so if you add the two together

8x+33+ 7x+27 =180

15x + 60 + 180

15x = 120

x= 8

so d's value would be 7(8) +27 = 83 degress

i think thats right, but its been a long time since geometry

[Skorpz]

thanks a lot rain.

[Rain]

no problem skorpz, thats what this thread is for:p

*is just glad people are using it*

[beautiful_death]

Does anyone know any race critical theory? I need help with my ethnic studies course.

[Agmaster]

Hahaha. I stoutly support this thread and will gladly help in essays regarding marketing, international relations, and Indonesia since my teacher has drilled it into my head.

[couch_kamote]

I support this thread too. If you want to ask anything about bussiness, economics, finance, marketing, accounting, and budget management; just post it here or PM me. I'll be glad to help you since I spent four years in college to study ad finish these courses. XD

You can ask me both random things too. Hehe

[Rain]

beautiful_death- i don't think i do:p (never heard of race critical theory)

couch_kamote- thanks, this thread isn't used very much, but its great that some people are willing to help

[Ravana]

Specifically 'race critical theory' or 'critical race theory'? Or are they interchangeable? Because I know some CRT stuffs... Depends on what you'd like to know. :p

[Skorpz]

me takes advantage of this again.

so my question is it possible to use the exterior angle sum theorem for concave polygons?

[beautiful_death]

Specifically 'race critical theory' or 'critical race theory'? Or are they interchangeable? Because I know some CRT stuffs... Depends on what you'd like to know. :p
Oh, I meant critical race theory XD

How the hell I got that mixed up.....beats me.
Well, any type of critical theory I don't get, even though I'm a senior in the university :noes

[Rain]

Skorpz- damn, i dunno

can you post a specific problem (would be easier for me to imagine)

BD- lol, i don't anything about critical race theory

[Skorpz]

that alright i probably just choose a different question to answer since there 4 to use from.

[Grey1x]

I'm only on the 9th grade, but I can easily help with Maths and Quimics / Physics about what I know.

[Rain]

Grey1x- thanks for being willing to help

the original plan was to have people listed for some subjects, but its just a Q & A type of situation right now

ill add you too the front though:D

[Kolbertt]

I'm needing some help with English-Japanese... Any kind and gentle soul willing to help please PM me

[Grey1x]

I'm in the front, rawr It seems like I'm inteligent xD.

[Rain]

Kolbertt- not too many people check this thread, i'd try PM'ing the people on the first post who speak japanese (i don't think they are on right now though)

sorry i can't be of more help

grey- indeed

[Grey1x]

Kolbertt: I know some japanese, not much and I really wonder I can help, but I can try. I know like counting from 1 to 100, movement, fighting, etc, things learnt at Karate.

Ask what you want, let's try anyway.

[Poiison]

lmao XD I guess I could help around.
I guess English would be the best for me to help in or any musical stuff you need. :lmao

480 on the SATs for a 7th grader would be decent yes? lol
and musical wise I've played at carnegie hall, princeton university and some other places. lol

[Rain]

480 as a 7th grader:eek: thats not much worse than what i got as a junior:p

thanks for being willing to help *added to front*

[Poiison]

Rain: lmao that was my writing score.
Ask me for math help and just no. lol
I got like a 440 there D;

No problem~

[Rain]

oh, i never took the writing section *feels old* :lmao

i totally crushed the math section:cool:

[Poiison]

Rain: lol that's cause I'm a good student, but I don't understand the formulas they use in college, no actually highschool :lmao

[Skorpz]

Does anybody have an idea of showing justice in a picture? have no clue on showing something that is fair and distributes benefits and burden of society.

i totally like using this

[Rain]

sorry, don't know what you mean:o

the closest thing i can think of right now is economics with supply and demand for the person and society:D

[Grey1x]

You want to show what is justice or what isn't justice?

[earthforge]

You can have a scale like as in economics. Then you can put either people or money on the scales.

[Revan1990]

I would agree with earth, a scale is the best thing to show or present something...

btw.
Maybe I could help too..
-English and Religion (my major subejcts)
-maybe economics too

[Shdo]

use that justice statue


http://www.dkimages.com/discover/previews/738/152471.JPG

[Revan1990]

use that justice statue
you mean Justitia? that was my first idea too, but I thought it's not what he wants...not sure

[Rain]

lol, this is why i was going to wait for skorpz to post until i gave more ideas, there are too many possible ideas for what he may want:D

Revan1990- oh, that would be cool, thanks, ill add you too the front:hug

[couch_kamote]

There are three basic categories of Justice.

Retributive justice or the lex talionis (law of retaliation) its kinda like, get punished if you do something wrong. Also it says that the proper punishment should be equal to the wrong suffered; "life for life, eye for eye, etc."

Distributive justice is more on the proper allocation of things - wealth, power, reward, respect - between different people.

Oppressive Law this is something I already forgot. Hehe

What category are you talking about?

Since the interpretations differ from each one.

[Revan1990]

just as an addition, I think Oppressive Law exercises a...uhhm kinda dictatorial(does that word exist?^^) approach to law or better legislation, it is unrelated to Juctice...something like a tyranny
I'm not sure about this, just think I remeber it was something like that...

[Skorpz]

the first thing i though of was a scale but that is always use to represent justice so i wanted to think of something new.

[Revan1990]

maybe you should explain what you want to show, more percise...

[couch_kamote]

just as an addition, I think Oppressive Law exercises a...uhhm kinda dictatorial(does that word exist?^^) approach to law or better legislation, it is unrelated to Juctice...something like a tyranny
I'm not sure about this, just think I remeber it was something like that...

Yup! I remember now. Oppressive Law exercises dictatorship. Good one. Hehe

[Malaena]

I'm really busy in college myself, but I come around on the weekends so I'd like to offer my services! I can help you in psychology, philosophy, sociology and english.

Psychology, sociology and english are what I do best. I can review an essay and advise you on changes you should make. I'm going for a Ph.d in psych so I'm confident I can help you with most questions concerning it. Sociology is my minor, so I have quite a good bit of knowledge concerning it as well.

[Rain]

Malaena- thanks for being willing to help (not many people need/use this thread, but it does help)

and a Ph.D in pysch:eek: thats awesome

is there any area that you're really interested in, or which theorist do you agree with most:D

[Malaena]

I really like Erik Erikson, his developmental stages seem spot on to me. I can look at everyone around me and place them in one. I love how he extended the stages, showing that people continue to develop across their life-span.

I know he was influenced by Freud (who I effing despise, but he wasn't completely crazy) but he took Freud's crazyness and refined it into something awesome.

Gah...there is more I like...I don't like the psychoanalytic approach even though I like Erickson's stages. I'm more of a cognitive/social learning theory fan. I like behavioral to an extent...but I don't believe people are just machines. Ah shit...lmao it's 9 and I have a night class! Adios!

[Rain]

Erikson's ideas were really good IMO too, and I also like the Cognitive/social learning.

Conditioning in general just makes the most sense to me, more so than the Id, Ego, SuperEgo and other stuff like Jung's anima and all that stuff

I could never really get into that

[kiera2]

Psychology, sociology and english are what I do best. I can review an essay and advise you on changes you should make. I'm going for a Ph.d in psych so I'm confident I can help you with most questions concerning it. Sociology is my minor, so I have quite a good bit of knowledge concerning it as well.

Don't suppose you know much about cognitive linguistics? A friend recommended Women, Fire and Dangerous Things to me - am loving the book and looking for something similar to read afterwards. (Haven't studied psych since my second year as an undergrad, but I find linguistics fascinating :P)

[myfinalheaven]

All I can recommend for a good read in linguistics is work done on semiotics by Roland Barths is a fascinating read if you like the area although you've probably read Barths but he examines symbols and signs and interpretation. Very good Read.

[kiera2]

To be honest semiotics isn't really my thing - more interested in language itself.

[Malaena]

Wow...I have no clue about cognitive linguistics! I really wish I could help you, but my english knowledge is mainly about how to compose a fantastic essay/paper and have it be in correct MLA (or APA) format.

You can wiki it and check out the books cited as source materials! *shrug*

[kiera2]

Haha, fair enough, I guess once you specialise in a PhD area you don't have much to do with other branches of psychology?

No big deal though, like I said, I'm not actually studying psych any more - I just find psycholinguistics fascinating.

[Rain]

what is psycho/cognitive linguistics about, it sounds interesting

is it abotu why we talk how we talk or somethign :crazy

[kiera2]

Psycholinguistics (As the name implies) is the psychology of linguistics. How the mind deals with language, how we acquire language, how language affects the mind, etc.

[Skorpz]

how do you find the length of the radius of a circle when you know the arc length and how much it measures.

[Rain]

you know the angle measure, and the arc length right

that arc length is equal to the angle (in radians) x the radius

so to find the radius you can take the length didvided by the angle measure (in radians)

[Skorpz]

so how do you convert the angle measure into radians.

[Rain]

multiply it by (pie)/180

i can't put the symbol of the computer

so if you have a 45 degree angle, that will be 45 (pie) over 180 which reduces to 1 (pie) over 4

[Skorpz]

does anybody know a great site that gives background information about same sex marriages like how the issue started and such. can't use wiki teacher said it was unreliable source.

[Shdo]

well you can use the sources at the buttom of the page of wikipedia, there are the sites that the site takes the info from.

[Revan1990]

can't use wiki teacher said it was unreliable source.
my teachers sai that too...they are so retarded...

well I would say there are many sites which provide good info on this topic, if you search with google, but the risk to get a not that reliable site is very high as well...I would recommend what shdo said, using the sources wiki uses, however sometimes this sites are pretty...uhmm yeah stupid, cuz sometimes the topic is not directly discussed...

well if you do not have to give a list of references, you can still use wiki, but if you have to then it gets complicated

[Hiraeth]

It usually helps to have a few websites that you go straight to in these situations

I believe encarta is usually a reliable source: http://encarta.msn.com/encnet/refpages/search.aspx?q=same+sex+marriage

And Howstuffworks has articles on everything from lockpicking, to psychology to quantum mechanics:
http://people.howstuffworks.com/marriage2.htm

Also try looking for newspaper articles, or things on university websites. Google Scholar is also a great resource for uni level work.

Use Wikipedia to get a general idea of what the topic is about, then use google to research specific things. What will determine whether a source is reliable or not is who has created it and for what purpose. The problem with wikipedia is that you or I could create an account and go in there and add anything, so it's an unreliable source.

[shinikage]

The reason wiki is not really reliable is because everyone can post and edit the articles. Sometimes, amateurs might do so after looking for some materials. Agree with Shdo, you could click the link provided by wiki. For a more valid source, I prefer to open the sites with .gov (government-made) or .org (organization) to which wiki usually also provide the link.

[Skorpz]

thanks a lot guy i will probably use encarta as my source. hope that is good enough with my teacher

0=====0

how do you find the measure of an arc?

here the question from the site. If O is the center of the circle below, and angle XOZ measures 76, what is the measure of xyz arc, in degrees?

[Rain]

skorpz- this should help

you know the angle measure, and the arc length right

that arc length is equal to the angle (in radians) x the radius

so to find the radius you can take the length didvided by the angle measure (in radians)

to get the arc lenth in degrees i think you just leave the angle in degrees

[Flying Banana]

can someone help me out? :sweat

um...well i'm doing english homework about that thing in CNN with Sarah Palin and her past and stuff
and i need stuff like Quotes and Bias
first of all

i need to know clearly what a bias is :lmao

help? D:

[Skorpz]

bias when you prefer one thing to another and don't give fair judgment to the other object. even if the thing they prefer is wrong.

[Rain]

bias when you prefer one thing to another and don't give fair judgment to the other object. even if the thing they prefer is wrong.

yeah

or, even simpler "when you judge anything just because its something"

it can be positive or negative

hiring just one race because you prefer that race, its a bias

or, with bleach, i think the arrancar should win cause i like them more, its a bias :XD

[emoloz]

Just check a few sites and see wheres she is being one sided with things.

[Skorpz]

can somebody *looking at rain* tell me what makes something a function or not a function.

[rayne_himura]

Any math geniuses out there? *looks at Skorpz and Rain* :lmao

Here's the problem:

Find b if the coeffecient of x^11 in the expansion of (x^2 + (1/bx))^10 is 15

Can anyone tell how the answer was gotten. And can anyone tell me the rule for expanding polynomials ?_?

[kiera2]

When you expand (a + b)^z the coefficients follow the z+1 row of Pascal's triangle as the powers of a and b increase/decrease.

For example (a + b)^2 gives you the terms 1(a^2) + 2(a)(b) + 1(b^2). The coefficients go 1, 2, 1 (third row of Pascal's triangle); the powers of a go 2, 1, 0; the powers of b go 0, 1, 2.

As a longer example, (a + b)^5, you take the 6th row of Pascal's triangle (1, 5, 10, 10, 5, 1) and apply it to a and b with increasing/decreasing coefficients:

1(a^5) + 5(a^4)(b) + 10(a^3)(b^2) + 10(a^2)(b^3) + 5(a)(b^4) + 1(b^5)

By applying the same methodology to your problem you can work out the coefficient of your x^11 term in terms of b, then use the number you have for x^11 to solve for b. (Obviously made trickier because your 'a' and 'b' themselves involve powers of x :p)

[ashido fan]

Physics question here.

If two objects of similar weight are placed in water, the buoyant force acting on it will be the same.

Then how about when that two objects are placed again in water, but one of it is added with an extra load on top.

Will the buoyant force still be the same?

My answer to this question differs from some of my friends. They say that the buoyant force is the same because both objects are floating.

But Archimedes' Principle states that (buoyant force) F=W(weight of water displaced/ weight of object) = pvg

and the v here is the volume of the object submerged in water.

In that question just now, both objects are fully submerged in water but one has more volume submerged in it. Moreover, the weight of the object with the load is obviously more than the one without the load.

If that is the case, the F=W stands. But what I don't understand is, not one, but so many of them thinks that the buoyant force is the same because both are experiencing floating.

They seem so confident of it, but it just doesn't make sense to me. Anyone here who can help?

[rayne_himura]

When you expand (a + b)^z the coefficients follow the z+1 row of Pascal's triangle as the powers of a and b increase/decrease.

For example (a + b)^2 gives you the terms 1(a^2) + 2(a)(b) + 1(b^2). The coefficients go 1, 2, 1 (third row of Pascal's triangle); the powers of a go 2, 1, 0; the powers of b go 0, 1, 2.

As a longer example, (a + b)^5, you take the 6th row of Pascal's triangle (1, 5, 10, 10, 5, 1) and apply it to a and b with increasing/decreasing coefficients:

1(a^5) + 5(a^4)(b) + 10(a^3)(b^2) + 10(a^2)(b^3) + 5(a)(b^4) + 1(b^5)

By applying the same methodology to your problem you can work out the coefficient of your x^11 term in terms of b, then use the number you have for x^11 to solve for b. (Obviously made trickier because your 'a' and 'b' themselves involve powers of x :p)

Thanks Kiera :wtf

Almost the same kind of stuff a friend from math club told me :lmao I guess I'll just have to read your post over and over again to fully understand it. Thanksss :hug

[Rain]

skorpz- something is a function if it a) is continuous across all points in its domain and b) produces just one y result for each x used (ie x won't give two answers)

ashido- if the two objects have are unequal weight but they are submerged the same amount their buyoncy force is different

the force provided by the water on the one object is greater than that on the other, because it is supporting an object that weighs more

I think your friends are mixing up density with all of this, but who knows

I believe you are right

[rayne_himura]

You got nothing to say on what I posted? :hm

[Rain]

You got nothing to say on what I posted? :hm

I thought you got your answer from kiera


*reads over*


Find b if the coeffecient of x^11 in the expansion of (x^2 + bx^-1))^10 is 15

I don't really understand what the problem is asking actually

no matter how you expand that function, there is no x^11, so i don't see how they are related :crazy

[Skorpz]

thanks rain was making sure good thing i check thought it was the other way around.

rayne i am not that good at math reason why i had to ask for help. but i wouldn't mind tutoring you if you know what i mean

[rayne_himura]

You confused me even more twinny :devestated haha Kidding, I get it nao. Thank you :hug

Skorpz :heehee Another study session perhaps?

[Nejibana]

This is a good idea, Rain. I can help with several subjects here:

-Maths
-Physics (specially electricity related physics)
-Spanish, English and a bit of French
-Technical drawing

[taramjwi]

I wish I had known about this place before I wrote my Cultural Reaction Paper ><

God I hate art <_<

[HELLA PINOY]

Ok personal training course scenario :XD

A man wants to start an excercise program. He is 45 yrs old and 200 lbs. He played football in High School but hasnt worked out in 14 years. Plan out a routine to get him back into a comfortable setting with training again.

Then a few scenarios later...

8 weeks after your routine the man tears a Quadracep muscle and has surgery to repair it. 2 weeks later he is back from rehab but still has a limp and cannot put alot of stress on his left leg. Plan out a new routine to both help his leg build up strength once more while not overstressing the muscles in his injured leg.

Thats my damn Homework! :lmao

[kiera2]

You got nothing to say on what I posted? :hm
I tried to give you everything you'd need to solve the problem without actually working out the answer for you - but if you want a full worked solution, click here (http://i6.photobucket.com/albums/y215/turky_ii/ii/rayne_maths.jpg).

(I tried typing it up but the notation was getting very confusing with all those indices :p)

[Skorpz]

can somebody explain to me how to find an equation of the regression line and how to find the value of the correlation coefficient

[Chikara]

Help me please! :noes

My topic is: Feminism/sexism in the English language
I have to write 1-2 pages...But I'm not a native speaker so it's difficult. xD

If you have examples like "if the word policeman exist,policewoman should too" or other thoughts,facts,please share them! :)

[Rain]

skorpz- do you still need help (sorry i missed the post before:noes)


chikara- http://en.wikipedia.org/wiki/Gender-specific_job_title

that gives ideas, and ideas of what to search for

it talks about including mostly nuetral titles, like police officer, not police man or woman

[Skorpz]

no i don't need any more help we actually didn't have to do those problem since most of the class didn't have graphing calculators

[hemagoku]

i need some social human rights examples please ,i got like 6 examples and the doc said they r all wrong and civil ,and i dunno any examples ,i tried searching but i just dunno what should i choose ,if someone please can help ,help me

about rain's re[ply in the last topic ,the doc said religion rights r considered civil which ruined 3 of my examples ,and said that brutality of police is civil 2 which ruined another 2 of my examples ,now i have no examples :cry i need a real example not just explain ,i tried google ,but didn't have good luck with it

[Rain]

another thing i found
Economic, social and cultural rights (ESCR) relate to the conditions necessary to meet basic human needs such as food, shelter, education, health care, and gainful employment. They include the rights to education, adequate housing, food, water, the highest attainable standard of health, the right to work and rights at work, as well as the cultural rights of minorities and indigenous peoples.


hema- he said religion was a religious one huh, that makes sense


others i just thought of

marriage
education
health care

another site http://cesr.org/unitedstates

Adequate Standard of Living
Cultural Rights
Education
Food
Health
Healthy Environment
Housing
Work

hope some of this helps some

[hemagoku]

can u give me example like in "some place (country or something)" they did "something (violation for example)" which violates the .... right of the social human rights

[Rain]

um:headscratch

ok, maybe....

Before the olympics, Beijing/China had a terrible smog problem and thus violats the right of providing a healthy enviroment

or...

the problem with having lead in the dg food from China violated the right of safe food


Im not quite sure if this is how they are supposed to be done:oops

[hemagoku]

thats so short ,but man u always the one to help me :)
but can u give me longer thing about China health environment problem

[Rain]

I don't know too much about it

I just recall it was a problem when it was decided that beijin would host the olympics and everyone was worried for the athletes safety, and then after that China worked to improve the quality of air in the town

but it wasn't as public a problem when it wasn't going to host an international sporting event, so the regular people were still at risk

[hemagoku]

sry 4 being annoying but can u help me searching for something full ,u know like something 1 page long or something ,but not hard ,i tried but i couldn't get good thing

[kiera2]

There are massive amounts of information at <Human Rights Watch (http://www.hrw.org/doc/?t=esc)>. A good topical issue might be the USA's use of torture on terror suspects. Or recent issues with habeas corpus. And there are far more serious issues in China than just clean air, as detailed <here (http://china.hrw.org/)>. <This one (http://news.bbc.co.uk/2/hi/technology/7696356.stm)> in particular might be of interest to the internet generation.

Pick a couple of interesting topics from HRW, do some research into the background behind them, and you'll easily be able to write a page about them.

[emoloz]

Help me please! :noes

My topic is: Feminism/sexism in the English language
I have to write 1-2 pages...But I'm not a native speaker so it's difficult. xD

If you have examples like "if the word policeman exist,policewoman should too" or other thoughts,facts,please share them! :)

Postman
Milkman
Airhostess/ flight attendant
The fact that countries are always called "She" O.o - in relation to possessions
Waitress and Waiter
Barber and Hairdresser
Paper boy

Can't think of anymore can compare the ones have given you I guess.

[kiera2]

Help me please! :noes

My topic is: Feminism/sexism in the English language
I have to write 1-2 pages...But I'm not a native speaker so it's difficult. xD

If you have examples like "if the word policeman exist,policewoman should too" or other thoughts,facts,please share them! :)
<This (http://faculty.ed.umuc.edu/~jmatthew/articles/sexinEnglish.html)> is quite a long essay but has some great examples. I've just read it, and I started copying and pasting paragraphs with really good examples but there were so many of them I figured it would be easier to let you read it yourself :p I'll just put a couple that were particularly good:

"...calling someone a manly man or a virile man is nearly always meant as a compliment. Virile comes from the Indo- European vir meaning 'man,' which is also the basis of virtuous. Contrast the positive connotations of both virile and virtuous with the negative connotations of hysterical. The Greeks took this latter word from their name for uterus (as still seen in hysterectomy). They thought that women were the only ones who experienced uncontrolled emotional outbursts, and so the condition must have something to do with a part of the body that only women have."

"The masculine wizard implies skill and wisdom combined with magic, while the feminine witch implies evil intentions combined with magic."

[hemagoku]

this one was nice http://china.hrw.org/press/news_release/china_hosting_olympics_a_catalyst_for_human_rights _abuses ,but it didn't say what are the violations ,it just said that china violated rights ,no examples of the violations ,help ?

[kiera2]

this one was nice http://china.hrw.org/press/news_release/china_hosting_olympics_a_catalyst_for_human_rights _abuses ,but it didn't say what are the violations ,it just said that china violated rights ,no examples of the violations ,help ?
You might just have to research the background information yourself. There are plenty of other links there, I'm not going to do all the legwork for you :p

(Edit: Okay, <just one link (http://china.hrw.org/press/news_release/china_olympics_harm_key_human_rights)>.)

[hemagoku]

thanks !!!!!!!!

[Lunar]

Add Math experts,calling all Add Math experts!!! :yell

Please help me~your help is much appreciated.

----------------------------------------------

Given that f:x--->a/x-b,f(3)=-5 and f(-5)=-1,find

a)The value of a and of b
b)The value of x such that the function f is undefined

/--->Denotes a fraction

----------------------------------------------

I'm bad at Add Math so in awhile,I might be posting help here :cry

[Rain]

Add Math experts,calling all Add Math experts!!! :yell

Please help me~your help is much appreciated.

----------------------------------------------

Given that f:x--->a/x-b,f(3)=-5 and f(-5)=-1,find

a)The value of a and of b
b)The value of x such that the function f is undefined

/--->Denotes a fraction

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I'm bad at Add Math so in awhile,I might be posting help here :cry

ok, here ya go ^^

f(x)= a/(x-b) is the equation right

next fill in the points that you were given into it

f(3)=-5

-5= a/(3-b)

solve this for a

-5 * (3-b) = a

-15 + 5b = a

then use the other point

f(-5)=-1

-1 = a/(-5 - b)

5 + b = a

you have like terms in a, so these two functions are equal

-15 + 5b = a = 5 + b

-15 + 5b = 5 + b

reduce this

4b = 20

b = 5

5 + b = a

5 + 5 = a

10 = a

so your answers are

b = 5, 10 = a

[Lunar]

*Spits out the water I'm drinking*

Rain-sensei (from now on I acknowledge you as my teacher XD) that is hella fast and this means you're quite good in Add Math or anything relating to it :D Yes,the answers are correct,lol I have the answers but I don't have the solutions to them.

I'm grateful for you,sensei~ :glomp

[kiera2]

God I miss high school maths. Things were so much simpler back then ;_;

If anyone knows anything about reduction products of digermenes feel free to drop me a PM.

[Rain]

God I miss high school maths. Things were so much simpler back then ;_;

it really was:cry good times though

If anyone knows anything about reduction products of digermenes feel free to drop me a PM.

I don't really know much about it:oops (I decided nott o take upper level chem courses :wha)

http://pubs.acs.org/cgi-bin/abstract.cgi/jacsat/2004/126/i34/abs/ja047090i.html

there is an abstract here and a link a full text

I doubt it's anything useful, but hey, it might be something

[kiera2]

I think I've already read that one actually! Spent a fair while on SciFinder catching up on relevant journals and stuff.

[shinikage]

b) the value of x such that f(x) is undefined

f(x) is undefined when the divider (what is the right english word for it? 0_o well, I mean the thing below lol ) is 0. So x-b=0 => x=b=5 , as Rain said ^_^
I miss math :cry

[Skorpz]

need help on matrices. need to know how to solve for x

3 1 multiply x= 10
0 2 adfdfsdf9 18

[moonflowers]

Hope it's not too late to help.... Skorpz, I need you to clarify the answer matrix first. What are its dimensions (ie. 1 column by 3 rows? 2 rows by 2 columns?)? The dimensions of x depend on the dimensions of the answer and the 2 x 2 matrix that x is multiplying. If the answer matrix is also 2 x 2, that means x will be 2 x 2 as well.

If A * x = B, then

A^(-1) * (A * x) = A^(-1) * ( B ) <-- order matters
x = A^(-1) * ( B )

So x is the inverted version of A, multiplied by B. To find A^(-1), see the formula under "Inversion of 2x2 matrices" under the Wiki link here. (http://en.wikipedia.org/wiki/Matrix_inverse#Methods_of_matrix_inversion)

[tifa]

I think I can help others with their Dutch and psychology questions? :wtf

[La`Punyeta]

need help on matrices. need to know how to solve for x

3 1 multiply x= 10
0 2 adfdfsdf9 18
well you need to clarify that adfdfsf9...

like moon said..you must need to have the inverse of variable A..

formula for the inverse is A^-1 = Adjoint of matrix A/ Determinant of A
to find it's inverse.. for example we have matrix [3 5][x1]=2
[2 1][x2]=18
find the determinant 1st of A which is 3(1)-(2)(5) = -7

now we find the adjoint..to do that we find the cofactor 1st of A which is pretty easy since this 2x2..if it's 3x3 it's different..

to find the cofactor in a 2x2 matrix, we just look at the number diagonallly opposite and that's the cofactor of that number
[3 5]
[2 1]
so the cofactor of this matrix is [1 2]
[5 3]


after that we examine the checkerboard.. [ + -]
[- +]
and we follow the signs and assign them to the corresponding numbers.. so..
[ +1 -2]
[ -5 +3]

then transpose this matrix
[+1 -5]
[-2 +3]
and you have the adjoint of the matrix..now we follow the formula

A^-1 = [+1 -5]
[-2 +3] <--- our adjoint
-----------
-7 <-- our determinant
so A^-1 = [-1/7 5/7]
[2/7 -3/7]

now we can find for x1 and x2

[x1] = [2] [-3/7 5/7]
[x2] = [18] [2/7 -1/7]

now multiply B and inverse of A and that will result to a 1x2 matrix..

and we'll have

[x1] = 88/7
[x2] = -50/7
or something like that :lmao


:lmao just follow these

[Lunar]

Can someone teach me how to balance a chemical equation?You can use any kinds of example as long as it is about Chlorine,Iron,Oxygen,Carbon Dioxide etc.I'm form 4 by the way :D So,not so much chemicals I knew then!

[Rain]

Can someone teach me how to balance a chemical equation?You can use any kinds of example as long as it is about Chlorine,Iron,Oxygen,Carbon Dioxide etc.I'm form 4 by the way :D So,not so much chemicals I knew then!

a chemical equation is balanced when it's outer shell is full, ie, has 8 electrons (unless it's the first shell which only contains 2)

so with carbon dioxide

Carbon has 4 in its outer shell (meanign 4 free), and oxygen has 2 open

so 2 of the carbons fill the oxygens remaining open, and the other 2 do the same with another oxygen

and 2 electrons from each oxygen also fill the carbon


these are called double covalent bonds (if memory my serves me correctly)


is this what you're asking for


edit- err sorry, I misread it at first, i thought you meant a chemical equation in balance :oops

try this site

http://dbhs.wvusd.k12.ca.us/webdocs/Equations/Balance-Equation.html

it should help explain it, hopefully

[Keylimepie]

Matty:ohh your mind seriously questions my belief in special powers:devestated

[kiera2]

Can someone teach me how to balance a chemical equation?You can use any kinds of example as long as it is about Chlorine,Iron,Oxygen,Carbon Dioxide etc.I'm form 4 by the way :D So,not so much chemicals I knew then!
A chemical equation is obviously related to equivalence. When you balance a chemical equation, you're making sure that, stoichiometrically, the two sides of the equation are equal.

For example, we know that methane (CH4) burns in oxygen (O2) to give combustion products of carbon dioxide (CO2) and water (H2O).

CH4 + O2 --> CO2 + H2O

But take a look at how many atoms there are on each side of the equation. One carbon on each side (CH4, CO2), so that's okay. But there are four hydrogens on the left (CH4), and only two on the right (H2O). So first, to balance out the hydrogens, let's make it two molecules of water:

CH4 + O2 --> CO2 + 2H2O

Now the hydrogen balances out, but what about the oxygen? There are 2 atoms of oxygen on the left (O2), but four on the right (CO2 and 2H2O). So let's make it two molecules of oxygen on the left, as well:

CH4 + 2O2 --> CO2 + 2H2O

Now the equation is equivalent - there are the same amount of atoms on each side. Obviously balancing equations can get a lot more tricky when more atoms are involved, but the basic idea of making both sides equal is always the same.

(For the record, if you find this stuff boring, don't let it put you off chemistry! Balancing equations in chemistry is the equivalent of learning to add and subtract in maths. Real chemistry is incredibly interesting, there's just a lot of boring groundwork you have to learn first, unfortunately...)

[Lunar]

@Rain:Hehe,it's okay!At least the site helps and your thought too :hug This is not your forte or maybe your memory didn't serve you well but you're a master in Math families :D

@Kiera2:I see,thanks!That is an in-depth explanation and yup,it's more tricky when more atoms are involved like what I'm doing now but I'll try it myself,thanks a million!!No,please never said science is boring to me,I find science very much interesting especially Bio since I'm a book worm not a 'calculator' but all science subjects have their own specialties :love

[ashido fan]

I find science very much interesting especially Bio since I'm a book worm not a 'calculator' but all science subjects have their own specialties
Gosh..you're just the direct opposite of me.:lmao
I love Physics and I intend to persue my studies in that area too.

Wait till you get my Bio teacher in form 5. You'll know what is called memorizing, key points, key points and moaarr key points!!:devestated

Try Bio at form 5 level. *no words*

[Lunar]

Wait till next year and I'll summarize Bio form 5,thanks for making me thrilled :lmao So,a pro Physicist,nice to meet you!But to say that I hate Physic is wrong,I love it as much as I love Bio and it's great to know that we're polar sides of each other :hug

P/S:Moar,need moar key points!! :yell

[La`Punyeta]

Chem is a killer :lmao
back in my days in high school..it was killing me..
im glad it's all over :yay

[Lunar]

True,true!Because of the equation and the chemical terms and names...

Mind blowing!But Chemistry is said to be in between Bio and Physic,so,what to do other than trying to mix those two :D

[ashido fan]

Chem is in between Bio and Physics? Quite true. When you take a Bio course in college, you need Chem. When you take a Physics course, you need Chem. But when you Bio, they don't ask for your Phy and vice versa. :lmao

And no, I didn't say you hate Phy. I am saying that you like Bio but I..well..*can't say it cuz it's taboo..SPM is coming* :p

[Skorpz]

so its a matrix 2x2 multiply by a matrix 2x1.
so its:
[31]
[02]
multiply by
[x]
[9]

equals
[10]
[18]

so how do you solve for X any certain formula to find it?
didn't understand the answer before so could you use less big words

[kiera2]

Chem is a killer :lmao
back in my days in high school..it was killing me..
im glad it's all over :yay
I hated chemistry in high school too. Now I'm doing a PhD in it xD (I actually wanted to be a physicist, but then I tried that at university and found it was all applied mathematics - I wanted something that felt a little more real, less theoretical.)

Chem is in between Bio and Physics? Quite true.
http://imgs.xkcd.com/comics/purity.png

(It does all get mingled though. I did a fair bit of quantum mechanics in my chemistry classes, and that's usually considered physics.)

[Lunar]

@Ashido Fan:Wow,you're form 5 student!!Good luck then for this coming SPM at Tuesday!

@Kiera:Heh,that diagram really shows how all of them mix together and lol at Mathematician :lmao (Math 'hater' here well slow in catching it not really hate ok :p) Wow PHD in Chemistry,I will try to take Science related course when in university according to my results but if I can't I'll be trying TESOL or something along that line :urahara At least something to do with languages especially English!I'm at least decent in English subject in my class and I enjoy this universal language :fu

P/S:Can someone help him?Poor Skorpz :cry

[La`Punyeta]

so its a matrix 2x2 multiply by a matrix 2x1.
so its:
[31]
[02]
multiply by
[x]
[9]

equals
[10]
[18]

so how do you solve for X any certain formula to find it?
didn't understand the answer before so could you use less big words
oh it was just one x...I thought it was two :lmao

there's no formula needed here..just basic matrix multiplication with algebra..


[3 1][x]=[10]
[0 2][9]=[18]


well you just mutliply the 2x2 by the 2x1 matrix..it's always row times column when multiplying so...



we multiply the 1st row of the 2x2 matrix by the colum of 2x1 matrix...
[3 1] < --- 1st row of 2x2 matrix
multiply
[x]
[9] <--- column of 2x1 matrix
equals
10

so that'll be
3(x) + 1(9) < -- eq 1
then we multiply the 2nd row of the 2x2 matrix by the column of the 2x1 matrix

[0 2] <--- 2nd row of 2x2 matrix
multiply
[x]
[9] < column of 2x1 matrix
equals
18

so we'll have.. 0x + 18 <-- eq 2
we can disregard x here since it's coefficent is 0
so
18 = 18

but we know a 2x2 multiplied by a 2x1 will have a product in 2x1 form
so we put eq 1 onto to the 1st row.. and eq 2 to 2nd row and equate them with the outer amtrix

[3x + 1(9)] = [10]
[0x + 2(9)] = [18]


[3x + 9] = [10]
[18] = [18]



we can ignore 18 = 18 coz it's already satisfied...

so we have 3x +9 = 10..and it's all basic algebra..

3x = 10 -9
3x = 1
x = 1/3

[3 1][1/3] = 10
[ 0 2][9] = 18

and if we multiply them to check...

[3 1] <-- 1st row of 2x2
times
[1/3]
[9] <-- column of 2x1
equals
10

3(1/3) +9 = 10
1 + 9 = 10
10 = 10

so the answer is x = 1/3


the explaining part is so hard to do...than solving the matrix.. :lmao

[kiera2]

the explaining part is so hard to do...than solving the matrix.. :lmao
Haha true, matrix multiplication is tricky to explain by typing it up :p To add to La Punyeta's solution, if you don't understand how matrix multiplication works, I really recommend going and reading up on it in a textbook.

[strawbErukia]

I often solve the matrix problem using calculator. Like my Math's teacher said, "Know your calculator well and you can cheat in the exams, wisely..." :D

Gosh..you're just the direct opposite of me.:lmao
I love Physics and I intend to persue my studies in that area too.

Wait till you get my Bio teacher in form 5. You'll know what is called memorizing, key points, key points and moaarr key points!!:devestated

Try Bio at form 5 level. *no words*

Physics huh? I bet you are good in Add Math too right?

Read. Understand. Remember. The key words, key points. Lol. That was exactly what my Bio teacher said. BTW, Bio is my fav subject. Mitosis, Meiosis... Bla3.. They are fun! XD

Good luck in your SPM next week! I don’t know, but yeah, usually the real one is easier than the trial papers. That was what happened to our batch anyway… ^^

[Skorpz]

thanks a lot La`Punyeta finally understand it

[kiera2]

I often solve the matrix problem using calculator. Like my Math's teacher said, "Know your calculator well and you can cheat in the exams, wisely..." :D
Thee are ways to set questions that can't be done with a calculator, though. Examiners love doing that for papers where they know students are allowed graphing calculators, to see who actually knows the theory.

[ashido fan]

Physics huh? I bet you are good in Add Math too right?
:lmao
I did better in my Add Maths than my Physics. :lmao

[La`Punyeta]

often solve the matrix problem using calculator. Like my Math's teacher said, "Know your calculator well and you can cheat in the exams, wisely...".
I do that too :lmao well we just use the calculator for just checking...solutions matter the most

skorpz - no problem :D

[Lunar]

Wow,looks like everyone excel in Add Math here,I only can follow Physic,Bio,Chemistry,EST well,the new subjects I mean but if it is Add Math,then it would be my worst subject ever,always get a C or D *facepalm*

At least I'm decent in Math,often got C,B or B+ :D

[ashido fan]

Gambateh, Lunar!!
Add maths is easy if you get your basics right and you practice. It's actually one of the subjects I can do while listening to music. No, I'm not bragging or anything, it's just that it's kinda mechanical. There is a pattern to the questions (for our education system) and at the end of the day, you'll find the questions similar. That's something not very good with our education system too. :p

The 1980s questions are mind boggling. Those are the toughies. :p

[melboyd~]

All the best to you ashido-fan ;) Add Math is something that needs constant practice, and like you said, doing past year's questions exercises will really help. Hi-5 for for doing add Maths or any other exercises while listening to music, that's one thing that keeps my mind moving. I do notice the cons for having similar questions format (mostly only the figures are modified), but at the end of the day, Add math in the matriculation or even form 6 will eventually be the same. You'll find the patterns recycled all over again in higher education ;D. Talking about SPM, I miss Add Math and Chemistry :p Also, Lunar-chan, glad that you choose TESL :hug

[IchiRuki143]

There's a sentence that never left my mind. Probably some or MOST of you knows it very well.

'Math is a hard subject.'

It is. But my teacher keeps saying that the more you tell yourself a subject is difficult, the more it will be harder for you to understand it. 'Till now, Math is one of my 'hate' subjects. I got lowgrades when I was in lower years of high school. But since last year, I got good grades. Still, I can't like it. It's hard. Everytime I see numbers, I swear I can feel birds flying above my head. :XD

[kiera2]

There's a sentence that never left my mind. Probably some or MOST of you knows it very well.

'Math is a hard subject.'
I don't think that's true at all. I always found maths to be incredibly logical and intuitive - it was my favourite subject at school. I couldn't stand subjects like history where I had to learn a whole lot of dates and events, I could never get them to stick in my head. With maths, once I understand a concept, I never forget it.

Of course, depending on individual strengths and weaknesses, it might take some people longer to reach that understanding than others. But once you get it and everything makes sense it's a great feeling.

When we were in high school, my best friend was struggling with Year 11 maths; I'd skipped a couple of years of maths at school so she asked if I could tutor her. We spent a whole weekend on calculus, starting at the very beginning with quadratics, until I was sure she actually understood what she was doing and why. She ended up getting an A+ for pretty much every bit of assessed work from then on. I certainly don't think that was due to any amazing teaching skill on my part - just that because I knew her so well, I knew how I could explain concepts in ways that would help her specifically to understand.

I think it's totally possible for anyone to get the hang of mathematical concepts, the problem is finding a way to reach that understanding that works for you personally. If you're willing to put in a little time and effort and really focus on how and why things in maths work the way they do, instead of just memorising formulae, you'll find the subject a lot easier.

[emoloz]

I think i have an intolerance to some maths. The stuff that made sense didn't and the complex stuff did xD I used to hate like long divison and stuff cause i always ended up getting something wrong in the calculation where as like pythagarous and stuff i could do no problem. Was odd xD

I was wondering anyone knew about the Holt 1978 social labouring theory at all. I kind of get whats its on about but i could do with a tad bit more information just to get my head around it. This is psychology btw if no ones got any answers am ok with it. Just my uni library and journals fail with much on it >.<

[kiera2]

I think i have an intolerance to some maths. The stuff that made sense didn't and the complex stuff did xD I used to hate like long divison and stuff cause i always ended up getting something wrong in the calculation where as like pythagarous and stuff i could do no problem. Was odd xD
That just means you're more of a real mathematician than a calculator :p Real maths is about understanding concepts, not chugging through pointless number work.

I'm afraid the psychology I've done was all very experiment-based, all about brain function and cognition rather than the social aspects of the subject, so I can't help you with Holt :(

[emoloz]

I probably am rofl thats what calculators are for though right to use for sums like that. Yeah stuff like Standard deviation which is confusing enough i cna do and anything algebraic am sorted at as well.

No worries, anyone else? If not its all good i just wanted to know if what i have is alright on him its not like vital just don't want it to crop up and my answers a bit wishy on him.

[La`Punyeta]

wow this thread turned into a math talk :lmao

Math for me is just simply following the rules. Follow the steps and know the properties invovled and you'll get the answer.

Applying math is the hard part...especially on electronics..one mistake and it can cost you your life..so do you maths properly!...our proff always told us that..:lmao

[zero_squad]

Wow, you just talk about math here :lmao

Ok, to talk about other thing, I have 3 questions from school that I need help. If you help me I'd be very glad:

1 - The average temperature of the Earth is bigger on January or July? Why?
2 - What would happen to the climatic seasons of the Earth if there wasn't the inclination of the rotation axis?
3 - Why the humanity, in the beggining of its agronomy development, after the hunter-collector era, expanded to the east-west direction and not to the north-south direction?


Glad if you help me :XD

[Rain]

1. the earth's average temperature eh

I'd think it would actually be in january

the earth's orbit isn't a circle, it's an elipse/oblong

the earth is closet to the sun in january, closer to the sun = more rays of heat hitting it


that would be my answer anyway


2. if the earth wasn't on a rotational axis than there would be no differing seasons, each area would just be the same the hole time

the average temp would be far more consistant


again, just my answer, not totally sure it's right



3. I'd assume it would have to do with the sunlight. They traveled in a direction that would give them the most light

have no clue about that one really

[zero_squad]

Anyway, thanks for your answers Rain :h5
They seem quite possible :wha

[kiera2]

Ok, to talk about other thing, I have 3 questions from school that I need help. If you help me I'd be very glad:
Rain's right about the first two - the Earth's orbit is elliptical, bringing it closest to the sun in January, so the planet's temperature is higher then. And seasons are caused because the Earth's axial tilt means either the northern or southern hemisphere leans towards the sun at different points in its orbit.

As for the third question, the spread of human populations was much easier in an east-west direction because their crops were much easier to transport east or west, to areas at the same latitude which therefore had similar climates. Food production is one of the most basic needs of any society, and foods that grow well in one climate are often completely useless in another. Travelling north-south you run into much more pronounced differences in climate - rain in summer instead of in winter, or lack of seasons entirely, for example - and so it was a lot easier for early humans to spread laterally. (There's a fantastic book on this kind of stuff, explaining all about how different human cultures advanced at different rates, called Guns, Germs and Steel, if you're interested.)

[zero_squad]

:yay

Thanks a lot kiera2 :hug
and Rain too :hug

You've helped me really A LOT :wha

[Amaranth]

Pretty basic math, but I need help cos SIMULTANEOUS EQUATIONS = MY BIGGEST WEAKNESS. Well kinda.

[Answers are in red. '/' represents a fraction.]

1) 3s² + 2t² = 11
3s + 2t = 1
s = -1, t = 2 OR s = 7/5, t = -8/5

2) 3x - 2y = 1
(x - 2)² + (2y + 3)² = 26
x = 1, y = 1 OR x = -9/5, y = -16/5

3) 3y - x = 3
2/3y - 1/x = 2
x = -1, y = 2/3 OR x = -3/2, y = 1/2

THANKS SO MUCH ;.;

[moonflowers]

The easiest way for me is to solve one equation for one variable, and then plug that into the other equation. It's long and not very clever, but my brain is only able to handle little bits of math at a time.

1) 3s + 2t = 1 <--- rearrange this to make it equal to s
s + (2/3)t = 1/3
s = 1/3 - (2/3)t

Plug this result into the other equation in the place of s:

3[(1/3 - (2/3)t)²] + 2t² = 11 <-- expand the squared term
3[1/9 - (4/9)t + (4/9)t²] + 2t² = 11 <-- multiply the 3 through
1/3 - (4/3)t + (4/3)t² + 2t² = 11 <--- combine t² terms
1/3 - (4/3)t + (10/3)t² = 11 <--- bring 11 = (33/3) to other side
-32/3 - (4/3)t + (10/3)t² = 0 <--- multiply both sides by 3
-32 - 4t + 10t² = 0 <-- divide both sides by 2
-16 - 2t + 5t² = 0

Solving with quadratic formula,
t = {-(-2) +/- sqrt[(-2)² - 4(5)(-16)]}/2(5)
t = {2 +/- sqrt[324]}/10
t = {2 +/- 18}/10
t = 2 or -8/5

Now that we've found t, we can use the first equation from before to find s by plugging in the values of t:
s = 1/3 - (2/3)t

If t = 2,
s = 1/3 - (2/3)(2)
s = 1/3 - 4/3
s = -3/3 = -1

If t = -8/5,
s = 1/3 - (2/3)(-8/5)
s = 1/3 - (-16/15) <-- rewrite 1/3 as 5/15
s = 5/15 + 16/15
s = 21/15 = 7/5

[La`Punyeta]

1) 3s² + 2t² = 11
3s + 2t = 1
s = -1, t = 2 OR s = 7/5, t = -8/5

2) 3x - 2y = 1
(x - 2)² + (2y + 3)² = 26
x = 1, y = 1 OR x = -9/5, y = -16/5

3) 3y - x = 3
2/3y - 1/x = 2
x = -1, y = 2/3 OR x = -3/2, y = 1/2




No.3

substitution method once agian..
x = 3y-3

sub this to the other equation

2/3y - 1/(3y-3) = 2

we perform LCD on the denominators and multiply them on all sides..

3y(3y-3) times [ 2/3y - 1/(3y-3) = 2]

so it'll become
2(3y-3) - 3y = 2(3y(3y-3))

simplifying it...

6y + 6 - 3y = 18y^2 -18y

if we simplify that...it'll result to..

18y^2 -21y +6 = 0

a = 18
b = -21
c = 6

http://upload.wikimedia.org/math/8/c/5/8c58ae2d322a3